Special Products Rule 1

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Expand $(4x + y)^2$

**Answer**

$\;\;\;(4x + y)^2$

$=(A + B)^2 \text{, where } A = 4x \text{ and } B = y $

$=A^2 + 2AB + B^2$

$=(4x)^2 + 2(4x)(y) + (y)^2 $

$=16x^{2} + 8xy +y^{2} $