Special Products Rule 1

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Expand $(3k + l)^2$

**Answer**

$\;\;\;(3k + l)^2$

$=(A + B)^2 \text{, where } A = 3k \text{ and } B = l $

$=A^2 + 2AB + B^2$

$=(3k)^2 + 2(3k)(l) + (l)^2 $

$=9k^{2} + 6kl +l^{2} $