Special Products Rule 1

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Expand $(3a + b)^2$

**Answer**

$\;\;\;(3a + b)^2$

$=(A + B)^2 \text{, where } A = 3a \text{ and } B = b $

$=A^2 + 2AB + B^2$

$=(3a)^2 + 2(3a)(b) + (b)^2 $

$=9a^{2} + 6ab +b^{2} $