Solve Quadratic Equations(Completing the Square)

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**Answer**

$x^{2}-9x+18=0$

or, $x^{2}-9x+18-18=-18$

or, $x^{2}-9x=-18$

or, $x^{2}-9x+\frac{81}{4}=-18+\frac{81}{4}$

or, $x^{2}-9x+\frac{81}{4}=\frac{9}{4}$

or, $\left(x-\frac{9}{2}\right)^2=\left(\frac{3}{2}\right)^2$

or, $x-\frac{9}{2}=\pm\frac{3}{2}$

or, $x =\pm\frac{3}{2}-\frac{9}{2}$

or, $x=-3$ and $x=-6$

There are two distinct solutions given by $x = -3$ and $x = -6$