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Question

Solve the quadratic equation for $x$ by using the factoring method.$$x^{2}-7x+12= 0$$

$x^{2}-7x+12= 0$
or, $(x-3)(x-4)= 0$
or, $x-3= 0$ or, $x-4= 0$
or, $x=3$ or, $x=4$
There are two distinct solutions given by $x=3$ and $x=4$