Standard equation of Ellipse

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Write the equation of the *ellipse* in standard from $$9x^{2}+64y^{2}+126x-512y+889 = 0 $$

**Answer**

$9x^{2}+64y^{2}+126x-512y+889 = 0 $

$9x^{2}+126x+64y^{2}-512y=-889$

$9(x^{2}+14x)+64(y^{2}-8y)=-889$

$9(x^{2}+14x+49)+64(y^{2}-8y+16)=-889+441+1024$

$9(x+7)^2+64(y-4)^2 = 576$

$\frac{1}{64}(x+7)^2+\frac{1}{9}(y-4)^2 = 1$

$\frac{(x+7)^2}{{8}^2}+\frac{(y-4)^2}{{3}^2} = 1$