Standard equation of Ellipse

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Write the equation of the *ellipse* in standard from $$x^{2}+16y^{2}-20x-64y+148 = 0 $$

**Answer**

$x^{2}+16y^{2}-20x-64y+148 = 0 $

$x^{2}-20x+16y^{2}-64y=-148$

$(x^{2}-20x)+16(y^{2}-4y)=-148$

$(x^{2}-20x+100)+16(y^{2}-4y+4)=-148+100+64$

$(x-10)^2+16(y-2)^2 = 16$

$\frac{1}{16}(x-10)^2+(y-2)^2 = 1$

$\frac{(x-10)^2}{{4}^2}+\frac{(y-2)^2}{{1}^2} = 1$