Greatest Common Divisor

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Find the *Greatest Common Divisor* (GCD) of the numbers 630 and 100.

**Answer**

$630=(2)({3}^{2})(5)(7)$

$100=({2}^{2})({5}^{2})$

The GCD of 630 and 100 is the product of the least powers of each prime factor in both.

Thus the GCD of 630 and 100

$=(2)(5)$

$=10$