Greatest Common Divisor

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Find the *Greatest Common Divisor* (GCD) of the numbers 252 and 1440.

**Answer**

$252=({2}^{2})({3}^{2})(7)$

$1440=({2}^{5})({3}^{2})(5)$

The GCD of 252 and 1440 is the product of the least powers of each prime factor in both.

Thus the GCD of 252 and 1440

$=({2}^{2})({3}^{2})$

$=36$