Finding zeroes of a polynomial

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Find the zeroes of the polynomial $3x^{2}+13x+12$

**Answer**

The polynomial $3x^{2}+13x+12$ is a quadratic polynomial and can be easily factored as $(3x+4)(x+3)$

So, $3x^{2}+13x+12 = (3x+4)(x+3)$

The solutions are:

$x = \frac{-4}{3}$

$x = -3$