Finding zeroes of a polynomial

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Find the zeroes of the polynomial $x^{2}-1$

**Answer**

The polynomial $x^{2}-1$ is a quadratic polynomial and can be easily factored as $(x+1)(x-1)$

So, $x^{2}-1 = (x+1)(x-1)$

The solutions are:

$x = -1$

$x = 1$