Finding zeroes of a polynomial

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Find the zeroes of the polynomial $2x^{2}-3x-9$

**Answer**

The polynomial $2x^{2}-3x-9$ is a quadratic polynomial and can be easily factored as $(2x+3)(x-3)$

So, $2x^{2}-3x-9 = (2x+3)(x-3)$

The solutions are:

$x = \frac{-3}{2}$

$x = 3$