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QuestionFind the zeroes of the polynomial $4x^{2}-7x+3$
AnswerThe polynomial $4x^{2}-7x+3$ is a quadratic polynomial and can be easily factored as $(4x-3)(x-1)$
So, $4x^{2}-7x+3 = (4x-3)(x-1)$
The solutions are:
$x = \frac{3}{4}$
$x = 1$