Quotient rule for derivatives

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Find the derivative $\;\;\;\frac{d}{dx}\left(\frac{x-8}{7x-3}\right)$

**Answer**

$\;\;\;\frac{d}{dx}\left(\frac{x-8}{7x-3}\right)$

$=\frac{(1)(7x-3)-(x-8)(7)}{(7x-3)^2}$

$=\frac{(7x-3)-(7x-56)}{(7x-3)^2}$

$=\frac{53}{(7x-3)^2}$