Quotient rule for derivatives

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Find the derivative $\;\;\;\frac{d}{dx}\left(\frac{2x-3}{9x-10}\right)$

**Answer**

$\;\;\;\frac{d}{dx}\left(\frac{2x-3}{9x-10}\right)$

$=\frac{(2)(9x-10)-(2x-3)(9)}{(9x-10)^2}$

$=\frac{(18x-20)-(18x-27)}{(9x-10)^2}$

$=\frac{7}{(9x-10)^2}$