Integral of exponential function

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$\int e^{-15-11x} \; dx$

**Answer**

$\int e^{-15-11x} \; dx$

Substitute $u= -15-11x$. So, $du = -11\; dx$, or $dx =-\frac{1}{11}\; du $

Then $\int e^{-15-11x} \; dx$

$=-\frac{1}{11}\int e^u \; du $

$=-\frac{1}{11}e^u + C $

Substituting back $u=-15-11x$

$=-\frac{1}{11} e^{-15-11x} + C$