Integral of exponential function

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$\int e^{7x} \; dx$

**Answer**

$\int e^{7x} \; dx$

Substitute $u= 7x$. So, $du = 7\; dx$, or $dx =\frac{1}{7}\; du $

Then $\int e^{7x} \; dx$

$=\frac{1}{7}\int e^u \; du $

$=\frac{1}{7}e^u + C $

Substituting back $u=7x$

$=\frac{1}{7} e^{7x} + C$