Integral of exponential function

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$\int e^{12x} \; dx$

**Answer**

$\int e^{12x} \; dx$

Substitute $u= 12x$. So, $du = 12\; dx$, or $dx =\frac{1}{12}\; du $

Then $\int e^{12x} \; dx$

$=\frac{1}{12}\int e^u \; du $

$=\frac{1}{12}e^u + C $

Substituting back $u=12x$

$=\frac{1}{12} e^{12x} + C$