Parabolas
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Question

Write the equation of the parabola $y=-2x^{2}-12x+7$ in the standard form. Then determine the vertex, focus, directrix and the axis of symmetry of the parabola. Also, state which way the parabola opens.

Answer

$y=-2x^{2}-12x+7$

$y=-2\left(x^{2}+6x\right)+7$

$y=-2\left(x^{2}+6x+9\right)+18+7$

$y=-2\left(x+3\right)^2+25$

$y-25= -2\left(x+3\right)^2$

The parabola opens down words.

The vertex is given by $V\left(-3,25\right)$

The focus is given by $F\left(-3,\frac{49}{2}\right)$

The directrix is given by $y= \frac{51}{2}$

The axis of symmetry is given by $x=-3$