Z-scores

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A data set is normally distributed with the *mean* value $\mu = 69.00$ and *standard deviation* $\sigma = 16.00$. Find the *z-score* of the data value $x = 82.00$

**Answer**

*z-score $z = \frac{x-\mu}{\sigma} = \frac{82.00 - 69.00}{16.00}=0.81$
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