Find the center and radius of the circle

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$\text{Find the center and radius of the circle given by the equation: }x^{2}+y^{2}-4y-12 = 0 $

**Answer**

$x^{2}+y^{2}-4y-12 = 0 $

$x^2+y^2-4y=12$

$x^2+y^2-4y+4=12+4$

$\left(x\right)^2+\left(y-2\right)^2 = 16$

$\left(x\right)^2+\left(y-2\right)^2 = {\left(4\right)}^{2}$

$\text{The center of the circle is }\left(0,2\right)\text{ and radius = }4$