A point on a line segment

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$\text{Find the point }P \text{ on the line segment joining the points }A\left(\frac{-6}{5},\frac{5}{3}\right)\text{ and }B\left(\frac{-5}{4},\frac{8}{3}\right)\text{ , such that }AP:PB =8:7$.

**Answer**

$\text{For the points }A \left(x_1,y_1\right) \text{ and }B\left(x_2,y_2\right)\text{ , if the point }P \text{ is such that }AP:PB=n:k \text{, then the point }P \text{ is given by:}$

$\left(\frac{(k)(x_1)+(n)(x_2)}{n + k},\frac{(k)(y_1)+(n)(y_2)}{n+k}\right)$$=\left(\frac{\frac{-92}{5}}{15},\frac{33}{15}\right)=\left(\frac{-92}{75},\frac{11}{5}\right)$