Equation of a line (Point/Slope)

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Find the equation of the line with slope $m=-3$ and passsing through the point $P\left(\frac{3}{5},-9\right).$

**Answer**

The equation of the line with slope $m$ and passing through the point $(x_0,y_0)$ is given by $$y-y_0=m(x-x_0)$$

Here $m=-3$, $x_0=\frac{3}{5}$ and $y_0=-9$

Substituting these values in the equation, we get

$ y-(-9)=-3(x-(\frac{3}{5}))$

or, $ y+9=-3(x-\frac{3}{5})$

or, $y+9=-3x+\frac{9}{5}$

or, $y=-3x-\frac{36}{5}$