You can view as many worked out examples as you want. First you are shown the question. Click Show Answer to view the answer. Click Show another Example to view another example. The best way to master mathematics is by practice. But practice requires time. If you don't have the time to practice, you can always view many practice problems completely worked out and become good at it too.
Level 1 Level 2 Level 3 Level 4 Level 5
Question

Solve $\frac{119}{x-3}-\frac{68}{x+3}-\frac{12}{\left(x-3\right)\left(x+3\right)}=-60$

Note that $x \neq3$ and $x \neq-3$

$\frac{119}{x-3}-\frac{68}{x+3}-\frac{12}{\left(x-3\right)\left(x+3\right)}=-60$

Or, $119\left(x+3\right)-68\left(x-3\right)-12=-60\left(x-3\right)\left(x+3\right)$

Or, $119x+357-68x+204-12=-60\left(x^{2}-9\right)$

Or, $51x+549=-60x^{2}+540$

Or, $51x+549+60x^{2}-540=0$

Or, $60x^{2}+51x+9=0$

The solutions of a quadratic equation $ax^2+bx + c = 0$ are given by$$x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$

In this quadratic equation, $a=60$, $b=51$, and $c=9$

Substituting these values of $a$, $b$ and $c$ in the above formula, we get

$x=\frac{-51\pm \sqrt{2601-2160}}{120}$

or, $x = \frac{-51\pm \sqrt{441}}{120}$

or, $x = \frac{-51\pm 21}{120}$

or, $x = \frac{-30}{120}$ and $x = \frac{-72}{120}$

or, $x=-\frac{1}{4}$ and $x =-\frac{3}{5}$

There are two distinct solutions given by $x = -\frac{1}{4}$ and $x = -\frac{3}{5}$